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According to the wikipedia article on file extensions Setlocal enabledelayedexpansion set file=c:\\users\\l72rugschiri\\desktop\\fs.cfg i want to do that without using any function or any goto The exact definition, giving the criteria for deciding what part of the file name is its extension, belongs to the rules of the specific filesystem used

Usually the extension is the substring which follows the last occurrence, if any, of the dot character How can i extract path and filename from a variable Png is technically the file extension, though you always look for the file.

145 i need to extract file name and extension from e.g

I don't know the name of file or extension and there may be more dots in the name, so i need to search the string from the right and when i find first dot (or last from the left), extract the part on the right side and the part on the left side from that dot 1 i think this is a better approach as matches only valid directory, file names and extension And also groups the path, filename and file extension And also works with empty paths only filename.

This will return empty for both file names end with And file names without an extension. This methods just checks the file extension of the file path It doesn't actually check the file bytes which may be different from the extension.

Why do you resolve() the path

Is it really possible to get a path to a file and not have the filename be a part of the path without that This means that if you're give a path to symlink, you'll return the filename (without the extension) of the file the symlink points to. Given the file name foo/bar.baz, we can say that foo/ is the dirname, bar.baz is the basename and.baz is the extname But is there a similar term that we can use for the foo/bar or bar part — i.e., the “file name sans extension”?

Given a string file path such as /foo/fizzbuzz.bar, how would i use bash to extract just the fizzbuzz portion of said string?

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